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MIT Libraries Puzzle Challenge

Puzzle Archive: Spring 2008 Puzzle 1 Solution

See the unsolved puzzle here.
Or go back to the Puzzle Archive.

Released February 22, 2008; deadline was March 3, 2008.
Congratulations to the winner of the drawing, Steven Sivek!

This puzzle is exactly what it looks like: a set of nine sudoku puzzles, where M, R, and sometimes 0 are allowed instead of some of the regular digits. The first step is to solve the sudokus; the solved grid looks like this:

Notice that each grayed string has the form MRxxxxxxx, and each digit or pair of digits denoted by corner markings (light slashes above) is between 1 and 26. Converting each of these numbers to the corresponding letter of the alphabet (1=A, 2=B, etc.) and reading across each "line" (that is, each set of three rows in the sudokus) spells out:

MATH
SCI
NET
MR
NUMBER

CROSS
REVIEWER
NAMES

This tells you what resource to use for these MR numbers: MathSciNet. MathSciNet is a carefully maintained and easily searchable database covering much of the mathematical sciences literature from 1940 to the present. This database contains not only bibliographic information for these papers, but also a review of each paper by another mathematician. The American Mathematical Society maintains and distributes MathSciNet.

Each entry in MathSciNet is assigned a unique number of the format MRxxxxxxx, and it is this number that the grayed string corresponds to. In MathSciNet, you can search for the paper with this number by changing the search option to "MR number." As the text implies, the important piece of information in each record is the reviewer's name. Those names are:

MR1346790=Santaló
MR0147936=Green

MR1257830=Ferrari
MR0851372=Tomkinson
MR2084937=Nieto
MR0987342=Karásek
MR0512493=Hillion
MR2013495=Clarke
MR1634028=Majewski
MR2038641=Hosono
MR1453268=Zemba
MR1658234=Svobodny
MR2018345=Foth
MR0215843=d'Orgeval
MR1346295=Tolstykh
MR1945263=Bhandari
MR0152839=Griffith
MR1859023=Oprea

To cross these names, we'd need to find a letter in each that is the same to cross them at. Fortunately, each pair of names only has one letter in common. Taking that letter and reading each row from left to right, we spell out the answer, Niels Bohr.

 

 


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